ITP Exercise Sheet 02

Discussion: 30 April 2026

{-# OPTIONS --allow-unsolved-metas #-}
open import Level using (Level)
open import Function.Base using (_∘_; id)
open import Relation.Binary.PropositionalEquality

Implicit universal quantification

If you want to write several functions that are all universally quantified in the same variable, this can be declared as follows:

private
  variable
     ℓ' ℓ'' : Level
    X : Set 
    Y : Set ℓ'
    Z : Set ℓ''

Reverse ∘ Reverse ≗ id

Since reverse is defined slightly differently in the lecture than in the standard library, we repeat the definitions here:

open import Data.List
open import Data.List.Properties using (++-identityʳ)

rev-acc : List X  List X  List X
rev-acc [] acc = acc
rev-acc (x  xs) acc = rev-acc xs (x  acc)

rev : List X  List X
rev xs = rev-acc xs []

Prove that reverse is its own inverse. For this it is necessary to prove an auxiliary lemma about rev-acc, i.e. the version generalised over the accumulator. (The type of the auxiliary lemma is below in the "Hints" section.)

rev∘rev≗id :  {X : Set }  rev  rev  id {} {List X}
rev∘rev≗id xs = {!!}

Binary representation

Define a function that converts a binary number into a natural number. There are two possibilities for which binary digits (bits) come at the beginning of the list: the least or the most significant bits. Define both variants:

(Hint: since the operators _+_ and _*_ are defined by recursion on the first argument, it is advisable to write constants on the left, e.g. 5 + (8 * x).)

open import Data.Bool
open import Data.Nat

--  binary representation "least-significant bit first"
lsb→nat : List Bool  
lsb→nat = {!!}

-- Once your definition is correct, you can enable the following
-- code as a test:
-- _ : lsb→nat (true ∷ true ∷ false ∷ true ∷ []) ≡ 11
-- _ = refl

-- Additionally define the conversion of binary numbers in the order
-- "most-significant bit first" to natural numbers, explicitly using
-- an accumulator:

msb+acc→nat :   List Bool  
msb+acc→nat = {!!}

msb→nat : List Bool  
msb→nat = msb+acc→nat 0

-- Once your definition is correct, you can enable the following
-- code as a test:
-- _ : msb→nat (true ∷ false ∷ true ∷ true ∷ []) ≡ 11
-- _ = refl
-- 
-- _ : msb→nat (true ∷ true ∷ false ∷ true ∷ []) ≡ 13
-- _ = refl

Show that LSB and MSB are equivalent; the type of the auxiliary function is below in the "Hints".

lsb≗msb∘rev :  (xs : List Bool)  lsb→nat (rev xs)  msb→nat xs
lsb≗msb∘rev  xs = {!!}

Map preserves composition

Prove that map is compatible with function composition:

map-preserves-∘ : {g : Y  Z} {f : X  Y}  map (g  f)  map g  map f
map-preserves-∘ {g = g} {f = f} = {!!}













Hints

Types of the auxiliary lemmas:

  • ∀ (xs ys zs : List X) → rev-acc (rev-acc xs ys) zs ≡ rev-acc ys (xs ++ zs)
  • ∀ (xs ys : List Bool) → lsb→nat (rev-acc xs ys) ≡ msb+acc→nat (lsb→nat ys) xs

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